Drive Failure Probability Calculator for RAID Arrays
Six drives at a 1.4 percent annualised failure rate carry a 34.6 percent chance that at least one fails within five years. With single parity the chance that two or more fail in that window is about 5.8 percent, and with double parity the chance that three or more fail drops to roughly 0.6 percent. Real risk runs higher than any of these figures because drives in one array share a batch, an age and a thermal environment.
Two numbers decide how nervous you should be about an array, and they are not the same number. The first is the chance that any drive fails, which is close to certain over a long enough horizon and is exactly what parity exists to absorb. The second is the chance that more drives fail than your parity can cover, which is the one that actually costs you the array. This calculator prints both.
| Year | Per drive | At least one fails | Array lost | Expected failures |
|---|
Array lost means more drives fail inside the window than your parity level can rebuild. The figure treats drives as independent and assumes a failed drive is not replaced during the window, so read the two sections below before quoting it at anyone.
How the probability is calculated
Everything here comes from one input, the annualised failure rate, which is the fraction of drives in a population that fail in a year of service. If a drive survives a year with probability 1 - afr, then it survives y years with probability (1 - afr)^y, so the chance one specific drive fails in that window is q = 1 - (1 - afr)^y.
From there the two headline figures follow:
- At least one of n drives fails: 1 - (1 - afr)^(n x y). Every additional drive is another chance to lose one, which is why an eight-bay array trips this figure so much faster than a two-bay.
- The array is lost: a binomial sum. The chance that exactly k of n drives fail is C(n,k) x q^k x (1-q)^(n-k), and the array survives only while k is no greater than the parity count p. Adding up every case where k is greater than p gives the loss figure.
With no parity at all, losing any single drive loses the array, so the two figures collapse into one. That is worth seeing once: set the parity selector to none and watch the loss number jump to match the failure number exactly.
What annualised failure rate should you use?
Published statistics from large operators, covering tens of thousands of drives, put modern 3.5 inch drives between roughly 1.0 and 1.6 percent per year across a fleet. The default here is 1.4 percent because it sits in that band without being optimistic. Individual models scatter widely around it, and a handful of historically bad models have run several times higher.
| AFR | When this is the right number to use | 6 drives, 5 years, at least one fails |
|---|---|---|
| 0.5% | The strongest models in published fleet reporting, in a cool environment | 14.0% |
| 1.0% | A good current NAS or enterprise drive in normal service | 26.0% |
| 1.4% | A sensible planning default across mixed models | 34.6% |
| 2.0% | Older drives, a warm cupboard, or heavy sustained workload | 45.5% |
| 3.0% | Drives past roughly five years of powered service | 60.3% |
| 5.0% | A model with a documented reliability problem | 78.5% |
Two curves distort a flat annual figure. The first is infant mortality: a meaningful share of drive failures happen in the first few months, from handling damage in transit or a manufacturing defect. That is the entire argument for burn-in testing a new drive before trusting it with data, because a drive that survives its first full surface pass and a couple of weeks of service is far more likely to survive the next several years. The second is wear-out, which starts climbing past roughly five years and never comes back down. Our drive reliability chart by model lists the published figures if you want to pick a rate from data rather than a default.
Why the array loss figure is not a forecast
Read this section before you act on the second output. The binomial model above assumes every drive fails independently, and drives in one array are emphatically not independent. They share almost everything that causes failures:
- The same manufacturing batch. Drives bought together often carry sequential serial numbers, so a batch-level defect reaches several members at once.
- The same age. Every drive crosses the wear-out threshold in the same few months, so the risk does not just rise, it rises for all of them together.
- The same heat and vibration. One failing fan, one warm cupboard in summer or one enclosure with poor damping affects the entire array.
- The same workload. They have written and read the same data for the same number of hours.
- The rebuild itself. Reconstructing a failed member means reading every sector of every survivor, for many hours, at the exact moment redundancy is gone. That is the single most stressful thing the array ever does, and it lands on drives that are all the same age.
The independent model understates correlated risk and overstates uncorrelated risk at the same time. It runs high because it assumes a failed drive is never replaced during the window, when in practice you replace and resilver within days. It runs low because the real second failure is far more likely to arrive during that resilver than chance alone predicts. Use these numbers to compare layouts and drive counts against each other, never as a prediction about your array.
The right response to both distortions is the same. Keep spare capacity and, ideally, a cold spare drive on the shelf so the rebuild starts the day the failure does. Buy drives across two orders or two retailers so they do not share a batch. And past roughly 8 to 10 TB per drive, use double parity, because the rebuild window is now measured in days.
How does drive size change the parity you need?
The probability of a drive failing barely moves with capacity. The consequence of one failing moves enormously, because the array is degraded for as long as the rebuild takes and rebuild time scales directly with drive size. A resilver writes the whole failed member back, at a realistic sustained 80 to 150 MB per second once the array is also serving files, and that arithmetic is what turns a capacity decision into a parity decision.
| Drive size | Rebuild at 80 MB/s | Rebuild at 150 MB/s | Parity to use | Example drive |
|---|---|---|---|---|
| 4 TB | 14 h | 7 h | Single parity is fine | WD Red Plus 4TB |
| 8 TB | 28 h | 15 h | Single parity, double on six or more bays | WD Red Plus 8TB |
| 12 TB | 42 h | 22 h | Double parity | WD Red Plus 12TB |
| 16 TB | 56 h | 30 h | Double parity | IronWolf Pro 16TB |
| 20 TB | 69 h | 37 h | Double parity, never single | WD Red Pro 20TB |
| 24 TB | 83 h | 44 h | Double parity, never single | WD Red Pro 24TB |
Set the calculator above to a one year window and read the loss figure, then remember that the exposure window during a 20 TB rebuild is two to three days, not a year. The annual probability is not the right scale for that moment. What is right is the observation that during those days you have no redundancy at all under single parity, on drives that are the same age as the one that just died, while reading every sector of all of them. That is why the recommendation flips at roughly 8 to 10 TB per drive, and why a 20 TB Red Pro should never sit in a single parity array regardless of what the annual arithmetic says.
Shingled drives break this table completely. SMR drives overlap tracks, so a random write forces a read-modify-write of a whole zone, and a rebuild that a CMR drive finishes in 30 hours can take an SMR drive several days. Some arrays have dropped the drive for timing out before it finished. Every drive named on this page is CMR, as are the Toshiba N300 and IronWolf lines, but the plain WD Red line historically included SMR models. Check before you buy.
What does a failing drive actually look like?
Drives rarely stop dead. Most give warning through SMART, the self-monitoring system built into every modern drive, and the array that catches the warning replaces a drive on a Tuesday afternoon instead of rebuilding at 3 am with no redundancy.
Four attributes carry almost all of the signal:
- Reallocated sector count. Sectors the drive has already retired and remapped to spares. Any non-zero value deserves attention, and a value that climbs over weeks is a drive on the way out.
- Current pending sector count. Sectors the drive could not read and has not yet been able to remap. This is the one that turns into an unrecoverable read error during a rebuild, which is exactly the wrong moment.
- Offline uncorrectable. Sectors that failed a scan and could not be fixed. Treat as pending sectors that have run out of chances.
- Command timeout and UDMA CRC error count. Frequently the cable or the backplane rather than the drive. Reseat before condemning, because a bad SATA cable has ended more healthy drives than it should have.
Two habits convert those readings into protection. Run a scheduled scrub or patrol read, monthly is a common cadence, so that every sector is read while redundancy still exists and a bad sector is discovered by the scrub rather than by a rebuild. And keep a cold spare on the shelf. A spare WD Red Plus 8TB sitting in a drawer turns the gap between failure and rebuild from a shipping delay into ten minutes, and that gap is the most dangerous period in the life of the array. Give it a full surface pass before shelving it, as covered in our guide to burn-in testing a new drive, so you are not discovering an infant mortality failure at the worst possible moment.
How much does parity actually buy you?
A lot, and more as the array grows. Take six drives at 1.4 percent over five years. The chance that two or more fail in that window is about 5.8 percent under single parity. The chance that three or more fail, which is what it takes to defeat double parity, is roughly 0.6 percent. That is an order of magnitude for the cost of one drive of capacity.
The comparison understates the real gap, because it only counts drives failing. It does not count the unrecoverable read errors that a single-parity rebuild cannot tolerate and a double-parity rebuild can. The RAID capacity calculator prints the read volume for a rebuild alongside the usable capacity for every layout, and our comparison of RAID 5 against RAID 6 works through the trade in full.
There is a cheaper lever than parity, and it is drive count. Six drives generate 50 percent more failure opportunities than four. Four 20 TB drives and eight 10 TB drives hold the same raw capacity, but the eight-drive array doubles the number of things that can break, doubles the power draw, and needs a larger enclosure. Where a build can be done with fewer, larger CMR drives, it usually should be. Our guide to choosing NAS drives covers which lines are CMR and why an SMR drive should never go into an array.
None of this is a substitute for backups
Every number on this page is about one failure mode: a drive dying. Parity handles that one well. It handles nothing else. Deletion, ransomware, a controller writing garbage to every member, a bad firmware update, theft, fire and flood all reach every drive in the enclosure at once, and no parity level on the list above protects against any of them.
Treat the array as the fast working copy and size a real second and third copy against it with the 3-2-1 backup sizing calculator. An array with a 0.6 percent chance of a parity-defeating failure and no backup is still one accidental delete away from total loss, and that probability is not on this page because it depends on you, not on the drives.
Frequently asked questions
What are the odds that a drive in my NAS fails?
With six drives at a 1.4 percent annualised failure rate, there is roughly a 34.6 percent chance that at least one of them fails within five years. The count matters as much as the rate: two drives over the same period come out near 13.6 percent, and twelve drives near 57 percent. More spindles means more chances, which is the argument for fewer larger drives rather than many small ones.
What annualised failure rate should I assume?
Published large-fleet statistics for modern 3.5 inch drives cluster between 1.0 and 1.6 percent per year, so 1.4 percent is a reasonable default. Two adjustments matter. Drives in their first few months fail more often, which is the infant mortality that burn-in testing is meant to catch, and drives past roughly five years climb steadily. A warm, vibrating enclosure pushes every figure upward.
Are drive failures in a RAID array independent?
No, and this is the honest limit of every probability calculator including this one. Drives bought together usually share a manufacturing batch, they accumulate identical power-on hours, they sit in the same heat and vibration, and they see the same workload. A rebuild then hammers every surviving member for hours. Real correlated risk is higher than any independent model reports, which is an argument for double parity.
Does RAID 6 really make that much difference?
Yes, and the gap widens with drive count. Six drives at 1.4 percent over five years give about a 5.8 percent chance of two or more failing under single parity, against roughly 0.6 percent for three or more under double parity, which is an order of magnitude. The practical advantage is larger still, because double parity keeps protecting you during the long rebuild after the first failure.
How long does a RAID rebuild take?
A 20 TB member resilvering at a realistic 80 to 150 MB per second takes roughly 37 to 70 hours, longer if the array is also serving files. That window is the reason drive size changes the parity recommendation: the array is degraded and reading every sector of every surviving drive for one to three days. Past roughly 8 to 10 TB per drive, use double parity.
Should I buy drives from different batches?
It genuinely helps, and it costs nothing but a little patience. Ordering from two retailers, or splitting an order across a few weeks, reduces the chance that every drive in the array shares a manufacturing defect. Mixing models between two reputable CMR NAS lines does the same. The gain is modest against random failure and meaningful against the batch-level problems that take out several drives at once.
How we choose: we compare published manufacturer specifications, drive datasheets, published reliability statistics and verified owner reviews. We do not test hardware in person, and we are not tied to any NAS vendor. Capacity and power figures here are researched guidance, not a warranty. RAID protects against drive failure, not against deletion, ransomware, fire or theft, so keep verified backups regardless of what any calculator tells you.
Working out your own cost per usable terabyte? The Home Server Build Planner is the paid version of these pages: 8 printable worksheets you fill in with your own numbers, plus the full PDF, $29.